video!
Mythbusters plan to uncover plane on conveyor belt
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Last: 5 yr ago by toucan82
be astute, mythbusters is moot
See, I told you it wouldn't take off
Mythmod says it airs on January 30th.
And the plane doesn't take off.
And the plane doesn't take off.
When will the episode get aired?
The conveyor is moot!
The conveyor is moot!
I swear to God I'm gonna pron blast this thread on my earlier posts to make it go away
Well if we could finally get everyone to agree that the plane will not take off, then the thread will fade into bolivian and you could rest easy.
Until that day however, expect to see the debate continue.
Until that day however, expect to see the debate continue.
ttt for Tree Hugger.
Has Tree Hugger seen this thread?
To those of you who do not know me, I am a chief engineer on a very high profile aircraft program.
Please accept this as the definitive answer to this question.
Here is how the question is formulated:
The answer is clearly no. When an air vehicle reaches Vr relative to some control volume of air it's in, it will take off. At Vr, the lift on the wings, which is purely a function of airspeed relative to the air vehicle, exceeds the weight of the air vehicle and it flies.
In the question, as posed, the air vehicle is traveling at V=0 relative to the air (except for any slight air flow at the surface of the conveyor belt due friction between the air and the belt) and thus will just sit there.
This is final - no discussion of wheel speed or length of conveyor belt or any of that other nonsense is relevant.
Please accept this as the definitive answer to this question.
Here is how the question is formulated:
quote:
"A plane is standing on a runway that can move (some sort of band conveyer). The plane moves in one direction, while the conveyer moves in the opposite direction. This conveyer has a control system that tracks the plane speed and tunes the speed of the conveyer to be exactly the same (but in the opposite direction). Can the plane take off?"
The answer is clearly no. When an air vehicle reaches Vr relative to some control volume of air it's in, it will take off. At Vr, the lift on the wings, which is purely a function of airspeed relative to the air vehicle, exceeds the weight of the air vehicle and it flies.
In the question, as posed, the air vehicle is traveling at V=0 relative to the air (except for any slight air flow at the surface of the conveyor belt due friction between the air and the belt) and thus will just sit there.
This is final - no discussion of wheel speed or length of conveyor belt or any of that other nonsense is relevant.
As you can see - no disscussion of this matter is ever final.
Perhaps, but anyone who does not take my word as final on this is an idiot and is cheapening my degree.
quote:
In the question, as posed, the air vehicle is traveling at V=0 relative to the air
Hooked another one?
How does the conveyor belt result in V=0?
I'm with you buddy - most of the engineers on this board are tards.
The CPA is moot!
Brian. Now dangit! I need you to go stir up the Oprah thread.
Holy **** that better be a troll...
I am cheapening HIS degree? Bwaaahahahaha....you sir are an embarrassment to both our school, your company, and anyone that has faith in you. Please shut your mouth before you embarrass yourself again. I find it funny that the people who think they are "qualified" to answer this question are the people that tend to get the answer even more wrong than the average joe.
I am cheapening HIS degree? Bwaaahahahaha....you sir are an embarrassment to both our school, your company, and anyone that has faith in you. Please shut your mouth before you embarrass yourself again. I find it funny that the people who think they are "qualified" to answer this question are the people that tend to get the answer even more wrong than the average joe.
Dear God, you can't be serious. Do you even understand how airplanes fly?
Yes, teh question is formulated exaclty such that the airplane must have V=0 relative to a bystander. Read the question I posted.
Yes, teh question is formulated exaclty such that the airplane must have V=0 relative to a bystander. Read the question I posted.
quote:
Yes, teh question is formulated exaclty such that the airplane must have V=0 relative to a bystander
It is not. You made an assumption.
quote:
"A plane is standing on a runway that can move (some sort of band conveyer). The plane moves in one direction, while the conveyer moves in the opposite direction. This conveyer has a control system that tracks the plane speed and tunes the speed of the conveyer to be exactly the same (but in the opposite direction). Can the plane take off?"
blah, nm....obvious troll
I answered that question. If you have a different one, post it.
I think the confusion on this issue is that everyone formulates the question a little differently.
I have posted the question as it is normally posted on the Internet and the answer is definitively NO the airplane will not fly.
Period.
I think the confusion on this issue is that everyone formulates the question a little differently.
I have posted the question as it is normally posted on the Internet and the answer is definitively NO the airplane will not fly.
Period.
quote:
This conveyer has a control system that tracks the plane speed and tunes the speed of the conveyer to be exactly the same (but in the opposite direction).
So ... yer point is?
quote:
Dear God, you can't be serious. Do you even understand how airplanes fly?
this gave him away.....just ignore him from now on, we don't need to start this thread going full speed again on someone that is just trolling
I'm glad he's trolling.
btw, you need to learn the subtle art of trolling a little better......
No trolling - the airplane does not fly.
would you be willing to put money on it?
The confusion seems to be that everyone thinks it's just a word riddle - it is not, at least not the way I worded it.
AginTX has to be yanking some chains here. Surely by now everyone realizes that regardless of how fast the conveyor is moving, the plane will take off.
quote:
would you be willing to put money on it?
If the experiment met the way I formulated the question, absolutley.
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