Glad the A's lost last night. That leaves the door open big time for Cleveland and Tampa Bay.
A's 94-63 (Angels, Mariners x4)
Rays 94-64 (Yankees, Blue Jays x3)
Indians 93-64 (White Sox x2, Nationals x3)
Uncle Charlie on the mound for the Rays tonight at home against the Yanks.
Pulled this from mlb.com's tiebreaker scenarios:Quote:
Three teams tie for two Wild Card spots
If the A's, Indians and Rays were all tied, the three teams would choose/receive A, B and C designations. Club A would host Club B, and the winner would advance to the Wild Card Game. Club C would then host the loser of the game between Club A and Club B to decide the other Wild Card team.
Again, the three designations are decided by head-to-head records. The A's went 9-4 against the Rays and Indians, the Rays went 9-5 against the A's and Indians, and the Indians went 2-11 against the A's and Rays. So the A's would have first pick of designation and the Rays second.
This would present a fun dilemma for the club with the first choice. Would the A's prefer two shots at advancement (one at home, and, if that doesn't go well, one on the road as Club A), despite the impact that might have on their pitching with yet another sudden-death game looming in the Wild Card Game proper? Or would they prefer to take their chances on a single home game (as Club C) for a chance to get to the Wild Card Game?