Can you solve this math problem?

5,978 Views | 48 Replies | Last: 2 yr ago by RobertHughes
Not a Bot
How long do you want to ignore this user?
AG
Imagine a car sitting at the bottom of a hill.

The hill is 1 mile to the top, and then 1 mile down to the bottom of the other side.

The car makes it to the top, but the car doesn't have a great engine so it only averages 15 mph on the way up.

How fast does the car have to travel going down the hill to complete the entire 2 mile journey with an average speed of 30 mph?
B-1 83
How long do you want to ignore this user?
AG
The treadmill is moot.
Being in TexAgs jail changes a man……..no, not really
concac
How long do you want to ignore this user?
AG
The answer is C.
StinkyPinky
How long do you want to ignore this user?
AG
Fast enough
Doctor Rosenrosen
How long do you want to ignore this user?
AG
Captain Positivity said:

Imagine a car sitting at the bottom of a hill.

The hill is 1 mile to the top, and then 1 mile down to the bottom of the other side.

The car makes it to the top, but the car doesn't have a great engine so it only averages 15 mph on the way up.

How fast does the car have to travel going down the hill to complete the entire 2 mile journey with an average speed of 30 mph?
It can't. It already wasted all it's time on the first half of the trip.
Anchorhold
How long do you want to ignore this user?
How long is left on the lease?
wbt5845
How long do you want to ignore this user?
AG
Warp 1
Doctor Rosenrosen
How long do you want to ignore this user?
AG
Doctor Rosenrosen said:

Captain Positivity said:

Imagine a car sitting at the bottom of a hill.

The hill is 1 mile to the top, and then 1 mile down to the bottom of the other side.

The car makes it to the top, but the car doesn't have a great engine so it only averages 15 mph on the way up.

How fast does the car have to travel going down the hill to complete the entire 2 mile journey with an average speed of 30 mph?
It can't. It already wasted all it's time on the first half of the trip.
Furthermore, if the down trek was 1.0000001 miles instead of 1 then it would be possible to average 30 mph.
Doctor Rosenrosen
How long do you want to ignore this user?
AG
dp
Dad-O-Lot
How long do you want to ignore this user?
AG
not possible
THE_CHOSEN_ONE
How long do you want to ignore this user?
Speed of light
ThunderCougarFalconBird
How long do you want to ignore this user?
AG
$potato. Duh.
The Porkchop Express
How long do you want to ignore this user?
AG
The doctor is his mother.
Ginormus Ag
How long do you want to ignore this user?
AG
I was told there would be no math.
Username checks out.
whoop1995
How long do you want to ignore this user?
AG
Sorry not a math major but wouldn't the second mile have to be made at 45 mph?

(X +15)/2=30

X+15=60

X=45
Ag81Golf
How long do you want to ignore this user?
What does the car's tits look like?
TriAg2010
How long do you want to ignore this user?
AG
whoop1995 said:

Sorry not a math major but wouldn't the second mile have to be made at 45 mph?

(X +15)/2=30

X+15=60

X=45


Negative - look at the minutes traveled. Averaging 30 mph means traveling one mile every two minutes. At 15 mph, it takes four minutes to reach the peak. You would need to travel instantaneously fast the last mile to average two minutes per mile.
whoop1995
How long do you want to ignore this user?
AG
TriAg2010 said:

whoop1995 said:

Sorry not a math major but wouldn't the second mile have to be made at 45 mph?

(X +15)/2=30

X+15=60

X=45


Negative - look at the minutes traveled. Averaging 30 mph means traveling one mile every two minutes. At 15 mph, it takes four minutes to reach the peak. You would need to travel instantaneously fast the last mile to average two minutes per mile.
Christ - 7 years of college, down the drain

Post removed:
by user
Eliminatus
How long do you want to ignore this user?
AG
whoop1995 said:

Sorry not a math major but wouldn't the second mile have to be made at 45 mph?

(X +15)/2=30

X+15=60

X=45
This is one of those low brow misleading word problems.

The key twist is here:
Quote:

complete the entire 2 mile journey

Must complete means a set boundary condition making it impossible to do since the condition was already met before any further calculations can take place.

"Got you good, you dumb piece of *****"
- whoever comes up with these things
aggie_wes
How long do you want to ignore this user?
AG
Who said you only had an hour to complete the trip?
whoop1995
How long do you want to ignore this user?
AG
Eliminatus said:

whoop1995 said:

Sorry not a math major but wouldn't the second mile have to be made at 45 mph?

(X +15)/2=30

X+15=60

X=45
This is one of those low brow misleading word problems.

The key twist is here:
Quote:

complete the entire 2 mile journey

Must complete means a set boundary condition making it impossible to do since the condition was already met before any further calculations can take place.

"Got you good, you dumb piece of *****"
- whoever comes up with these things
Thanks to all of you for the explanation - jacked that one up big time
Eliminatus
How long do you want to ignore this user?
AG
aggie_wes said:

Who said you only had an hour to complete the trip?
The problem statement. The units matter. They use mph which is a function of time and length. The key statement I pointed out above sets a condition of 2 miles completed. Meaning for mph to stay true, the time is now also set.

So with the time being set, you have to calculate for that time.

Variables: 2 miles is known, time is not, must equal 30mph.

Some basic algebra and it is found that the car must travel one mile every 2 minutes to average 30mph.

However the first part of the equation of reaching the top at 15 mph means 4 minutes have already been used. You can't have that and have the second part of the question also be true invalidating the whole thing.
Condition of 30mph avg. was already passed half way up the front side.

For the record, I hate these.
Eliminatus
How long do you want to ignore this user?
AG
whoop1995 said:



Thanks to all of you for the explanation - jacked that one up big time
Eh, these are just word traps designed to trick people. I only know this one because I ran across something similar years ago.
Anchorhold
How long do you want to ignore this user?
GB idiots have reading comprehension problems? GASP So that's why so many people can't follow rule one.
AgsMyDude
How long do you want to ignore this user?
AG
Does the driver has big cans?
toucan82
How long do you want to ignore this user?
What if you used negative time?
213 Grove
How long do you want to ignore this user?
AG
Sticks&Stones
How long do you want to ignore this user?
AG
Captain Positivity said:

Imagine a car sitting at the bottom of a hill.

The hill is 30 miles to the top, and then 30 miles down to the bottom of the other side.

The car makes it to the top, but the car doesn't have a great engine so it only averages 30 mph on the way up.

How fast does the car have to travel going down the hill to complete the entire 60 mile journey with an average speed of 60 mph?


Change the variables to something easy to work in your head.

To average 60 mph over a 60 mile trip, you have to complete the trip in exactly one hour. You already used exactly one hour traveling the first 30 miles at 30 mph.

It can't be done
azul_rain
How long do you want to ignore this user?
im a business major **********, i put logos on power points and deal with the ******* people
lb3
How long do you want to ignore this user?
AG
Where is physics clown when we need him?

Damn you PhotoBucket!
ABATTBQ11
How long do you want to ignore this user?
AG
15 mph since it takes the tunnel through the hill and is a piece of ****
ABATTBQ11
How long do you want to ignore this user?
AG
Seems appropriate

Not a Bot
How long do you want to ignore this user?
AG
The solution:
Ghost91
How long do you want to ignore this user?
Depends. What was in the kitchen?
Page 1 of 2
 
×
subscribe Verify your student status
See Subscription Benefits
Trial only available to users who have never subscribed or participated in a previous trial.