TriAg2010 said:

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whoop1995 said:

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Sorry not a math major but wouldn't the second mile have to be made at 45 mph?

(X +15)/2=30

X+15=60

X=45

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Negative - look at the minutes traveled. Averaging 30 mph means traveling one mile every two minutes. At 15 mph, it takes four minutes to reach the peak. You would need to travel instantaneously fast the last mile to average two minutes per mile.

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Challenge accepted!

It's theoretically possible if you are a massless particle taking a Feynman wave function path, but you'd never really know which path was taken. Cars are not massless particles, though.

Now do mass transit.

you can't travel instantaneous at the end and do it, you have to use this

Captain Positivity said:

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Imagine a car sitting at the bottom of a hill.

The hill is 1 mile to the top, and then 1 mile down to the bottom of the other side.

The car makes it to the top, but the car doesn't have a great engine so it only averages 15 mph on the way up.

How fast does the car have to travel going down the hill to complete the entire 2 mile journey with an average speed of 30 mph?

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2mi/30mph = 4min to complete the journey.

1mi/15mph = 4min to get to the top.

You're now in a DIV/0.

2 miles at 30 mph = 4 minutes

1 mile at 15 mph = 4 minutes

No time left to average the whole trip at 30 mph, unless there's some rounding involved.

88 mph

0

You can go a million miles an hour but still can't make it work as the time spent is more than your allotted time for the total trip.

X/o = null set.

wbt5845 said:

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Warp 1

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So no credit for giving the first correct answer?

wbt5845 said:

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wbt5845 said:

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Warp 1

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So no credit for giving the first correct answer?

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Seeing as how that's incorrect, no.

THE_CHOSEN_ONE said:

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Speed of light

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Too slow.

ERR/0 is faster.

Oh, tough question. Math is the most complicated discipline for me; if I don't have a formula, I cannot solve something. And it's a problem for me because I have math twice a week, and I have to do homework, and there are a lot of tasks to do. I have a tutor, and she helps me to understand everything better, and I also use this site https://plainmath.net/secondary when I need help with solving. There I can find similar tasks and see how everything was solved, or post my own question and get step-by-step solving help. It's a great helper for students, and some guys from my group also use that.