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Divisional Champion: The (eligible) team with the best winning-percentage of all divisional members in its eight conference games is declared the divisional champion and representative to the Dr Pepper Big 12 Conference Football Championship Game. A team ineligible under NCAA or Big 12 rules for postseason (bowl) competition shall not compete in the Championship Game.

Divisional Tiebreakers: The following procedure will determine the representative from each division in the event of a tie:

If two teams are tied, the winner of the game between the two tied teams shall be the representative.
If three or more teams are tied, steps 1 through 7 will be followed until a determination is made. If only two teams remain tied after any step, the winner of the game between the two tied teams shall be the representative.


1. The records of the three teams will be compared against each other
2. The records of the three teams will be compared within their division
3. The records of the three teams will be compared against the next highest placed teams in their division in order of finish (4, 5 and 6)
4. The records of the three teams will be compared against all common conference opponents.
5. The highest ranked team in the first Bowl Championship Series poll following the completion of Big 12 regular season conference play shall be the representative in the Big 12 Championship Game, unless two of the tied teams are ranked within one spot of the other in the BCS poll. In this case, the head-to-head results of the top two ranked tied teams shall determine the representative in the Big 12 Championship Game.
6. The team with the best overall winning percentage (excluding exempted games) shall be the representative.
7. The representative will be chosen by draw.

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Does tiebreaker #1 refer to conference or overall record? If it refers to conference, then there is this possibility: Oklahoma wins out (beating OSU), and A&M wins out, leaving both teams tied with OSU for the lead in the South. The winner would then be declared under tiebreaker #4. Under rule number 4, do all three of the tied teams have to play the same common conference opponent, or just two of them? If not, this would happen: OU and A&M both lost to Mizzou, but OSU did not play Mizzou. However, OSU lost to Nebraska and with an A&M victory over Nebraska, OSU would be knocked out; leaving the head to head result between A&M and OU as the final tiebreaker. Say rule #4 does not apply, and it comes to rule #5. In this scenario, A&M still has a small chance to be ranked higher than both teams with a win over high ranked Nebraska.

Where am I wrong, what are your thoughts......

In other words, OU wins out and we control our own destiny.

It looks like it, because #6 deals w/ overall winning %.

I believe tiebreaker #1 refers to the three teams records against each other - i.e. in this scenario, each team would be 1-1 against the other.

I disagree with the interpretation on #4 - there are no common north teams that all three teams played, so there are no common conference opponents outside of the three south teams.

If we win out, and OU beats OSU, it will come down to BCS rank. We'll have a hard time jumping them in the human polls, but the computer may help us with strength of schedule.

If it comes down to rankings, hopefully a win over Nebraska will move us above OU and a late season loss for OSU will knock them out.

Agsuffering@bulaw, there is no way the tiebreak won't be settled after #5. But even if it were possible, OU and OSU would be 10-2 and A&M would be 9-3, giving them a higher winning %.

If we win out and OU wins out, then don't we both have 2 in conference losses but we have the head to head victory?

Yes we have the head to head over OU, but OSU will have the head to head over us, and OU will have it over OSU. That is why it is a three way tie, not two way.

Yeah as soon as I typed it I remembered the thread title about THREE WAY tie. Pretty proud of myself right now.

If we win out and OU wins out, there is a good chance we go because our three wins, including one against a higher ranked team in Nebraska, over an OU win over OSU should give us the edge in the BCS

y'all need to stop counting chickens, dang it. Nebraska is going to be very very tough. not to mention gaylor and sips.

Just curious about the possibilities. It feels good to be in the race in November, might as well enjoy it while you can.

Okielite needs to drop two games from the following list: tu, ku, ou. From our perspective, a stunning loss to ku followed by a loss to ou would be the best of all worlds, assuming we win out and ou does not have a meltdown against baylor or tceh.

But first things first: BTHObu!!!

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2. The records of the three teams will be compared within their division

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The way I read it is, if A&M and OU win out, and OSU finishes 6-2 in conference there will be a 3 way tie. All teams will be 6-2 in conference. All teams will be 4-1 in the south division.
Go to step 3

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3. The records of the three teams will be compared against the next highest placed teams in their division in order of finish (4, 5 and 6)

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This doesn't make much sense, because this would be the rest of the division, if you're tied after step 2, you'll be tied after step 3.

Step 4...how does that work if only two of the three played someone..NU for example. Would osu be eliminated at that point the head to head with us and blow u?

Those tiebreakers are full of redundancy...

however, I used to think the same thing about #1, but there is a way that, looking at the three teams records against simply the three tied teams, you can have them set up where one team is 2-0, one team is 0-2 and one team is 1-1, in which case the 2-0 team would be the winner.

That will not be the case this year... the only way a three way tie can happen is if OU beats OSU which would make the three of us all 1-1 in the TAMU, OSU, OU circle.

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This doesn't make much sense, because this would be the rest of the division, if you're tied after step 2, you'll be tied after step 3.

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Nope. If the tied teams finish each with two losses in the South, then it's possible #3 would break the tie: say two of the teams also lost to the #5 team and the third lost to the #6... third team is eliminated.

[This message has been edited by Dr. Teeth (edited 11/7/2010 8:56p).]

1. The records of the three teams will be compared against each other
TAMU (1-1) v. OU & OSU
OSU (1-1) v. TAMU & OU
OU (1-1) v. TAMU & OSU

2. The records of the three teams will be compared within their division
TAMU (4-1) v. OU, OSU, t.u., BU, and TT
OSU (4-1) v. TAMU, OU, t.u., BU, and TT
OU (4-1) v. TAMU, OSU, t.u., BU, and TT

3. The records of the three teams will be compared against the next highest placed teams in their division in order of finish (4, 5 and 6)
Redundant since there are only 6 teams in the division

4. The records of the three teams will be compared against all common conference opponents.
Redundant because the only conference opponents we all have in common are our division opponents

5. The highest ranked team in the first Bowl Championship Series poll following the completion of Big 12 regular season conference play shall be the representative in the Big 12 Championship Game, unless two of the tied teams are ranked within one spot of the other in the BCS poll. In this case, the head-to-head results of the top two ranked tied teams shall determine the representative in the Big 12 Championship Game.
At this point it could be possible that TAMU, OSU and OU are ranked closely in the BCS poll, except I have a feeling that OU might get a little more love by the voters just because... if us and OU are the highest, and within one spot of eachother, we go... If it's us and OSU within one spot, they go... If it's OSU and OU within one spot, OU goes...

6. The team with the best overall winning percentage (excluding exempted games) shall be the representative.

Given the result in #5, the only way this happens is if the three tied teams are all ranked consecutively in the BCS... pretty unlikely

This is where the Arky loss hurts us

7. The representative will be chosen by draw.

by this time, the only real way to get here would have been for each of the three teams to have a single loss in a circle, with equal strength of schedules, and unbiased voters. This will happen shortly after bovine lay eggs.

[This message has been edited by TexasRebel (edited 11/7/2010 9:01p).]

Thank you TexasRebel

Root for tech against OU!

The real question is... if we win out and Oklahoma ends up playing Nebraska for the Championship, do we get to put up a "2010 Big 12 Champions*" sign in our locker room?

[This message has been edited by Dr. Teeth (edited 11/7/2010 9:25p).]

I know that you are making a reference to the Texas asterisk deal, but we would be Big 12 south co-champions and have a trophy

texasrebel, you are missing one very important point:

"If three or more teams are tied, steps 1 through 7 will be followed until a determination is made. If only two teams remain tied after any step, the winner of the game between the two tied teams shall be the representative."

Assuming OU wins out, A&M wins out, and OSU only loses to OU, I believe the tiebreaker may be solved in #4:

Common Opponents:
- A&M: beat Neb, loss to MU, loss to OSU
- OSU: loss to Neb, OU, beat A&M
- OU: loss to MU, loss to A&M, beat OSU

Would this eliminate OSU since we beat Neb?


[This message has been edited by gr8yt21 (edited 11/7/2010 10:40p).]

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Common opponents of all three teams. There are no north teams who have played ou, ok st and a&m, thus there are no north common opponents. There are three common opponents, tech, texas, and baylor and each team is 3-0 against them (in this scenario).

No, Nebraska isn't a common opponent between all three teams.