Wonder what y'all got and how y'all did it

The semester is over. Why are you doing homework?

I think I would just google that bs.
I ain't got time for that

There isn't enough information. The width must be known to answer this question.

And looking at the answers, the width would need to enormous. The rectangular solid would need to be about 5ft long to be only 1 ft^3. And then it would only weigh 395lbs.

Also the orientation of the cylinder matters. Is the height of the cylinder equal to the length, width, or height of the rectangular solid?

Overall it's a very stupid question.

With my rusty math skills, would I be wrong to say any of those answers could be correct if you solve for "x" using them as your starting point? As someone said, the orientation of the cylinder is more than slightly important.

BRB. Gonna go remove said cylindrical object from your mom a few times to experiment and figure this out for ya.

ChemAg15 said:

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There isn't enough information. The width must be known to answer this question.

And looking at the answers, the width would need to enormous. The rectangular solid would need to be about 5ft long to be only 1 ft^3. And then it would only weigh 395lbs.

Also the orientation of the cylinder matters. Is the height of the cylinder equal to the length, width, or height of the rectangular solid?

Overall it's a very stupid question.

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It's a very easy question. There's nothing difficult about it. The answer is right in front of your eyes.






If you can employ liberal math.



/S

Not near enough info. Some idiot teacher altered the question from a question bank and didn't know what they were doing. Then another teacher probably reused the same mistake.

Looks like they accidentally used " instead of '… and on top of that, didn't give you x. But assuming the cylinder runs parallel to the length of a 10' solid and x = 4', then the answer could be B.

None of the other answers are a round number for x

I suppose the question doesn't say what the rectangular solid is made of. If we assume it is made of micro aggressions and oppression I could see how the question makes sense.

Holy redaction technique!!!

It is a good thing that you or your 6th grader aren't working on the Epstein client list or that shooter manifesto with those skills.

Instead of saying weighs "lbs per cubic foot" just say density.

I don't remember solving for "x "in 6th grade but could be wrong.

I agree you need to know the width so you can then subtract out the cylinder center.

Anchorhold said:

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BRB. Gonna go remove said cylindrical object from your mom a few times to experiment and figure this out for ya.

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Your mom's box would have been perfect for this joke

It looks like part of the answers have been whited out.

I always "Ask Alexa" all of that stuff and run with the answer.

Yeah, don't think I ever did math like that in the 6th grade.

The problem probably assumes the cylinder length is same as X or was show that way on some sketch that is missing. But, assuming that;

The weight equals Volume times 395.

The volume is 30X - piX. (Also, Have to convert inches to feet or vice versa)

So, they probably meant to provide the volume of either the cylinder or the rectangle, but didn't. You need some other piece of information to work this problem.

I should know this... my Uncle's a painter.

Is it an African rectangular solid or a European one?

$240 Worth of Pudding said:

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Is it an African rectangular solid or a European one?

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And is it laden or unladen?

there is no dimensional integrity if the width is greater than the length, for then it would be the length. a simple diagram would suffice, but i suppose trying to create one would illustrate how illogical this problem is. if youre going to make a word problem, make it make sense or just stick to diagrams with equations.

What about your chode dick? That's wider than it is long.

Trade school is so much more worthwhile than answering that stupid question.

Lol there is no way that is a 6th grade Q

Fake question. No mention of trans rights or how evil whitey is.