The word "the" is not in the original question.
quote:In short: sqrt(x^2)=abs(x).
Sqrt(4) = x
4= x^2
All I did is square both sides. You've admitted x^2=4 has 2 solutions. So what changes?
quote:Really? Clearly it's common usage.
The word "the" is not in the original question.
quote:quote:Really? Clearly it's common usage.
The word "the" is not in the original question.
quote:You doubt that a question on TexAgs (general board) is common usage? You are smoking crack.quote:quote:Really? Clearly it's common usage.
The word "the" is not in the original question.
In math, when you have to use clearly to cover your shoddy work, you've lost.
quote:That would be common usage, not mathematical usage and certainly not in any math course from algebra II on.
From your link:quote:(which is the positive one)
In common usage, unless otherwise specified, "the" square root is generally taken to mean the principal square root.
quote:This is a load of crap. I worked for the math department at A&M teaching math, have been an engineer for decades, and been programming for longer than that. Under none of those circumstances does anybody use anything like sqrt(4)= +-2. Mathematica and Maple, both of which are used by mathematicians and scientists world wide does not treat and both return multiple roots when proper. Every computer language I know of, C, C++, Java, Python, Ruby, javascript, and countless others ALL treat sqrt(x) as having a single answer. To pretend that 99.99999% of people use the common usage of sqrt as the principal square root is delusional. Clearly a question asked on the general board of TexAgs is common usage.quote:That would be common usage, not mathematical usage and certainly not in any math course from algebra II on.
From your link:quote:(which is the positive one)
In common usage, unless otherwise specified, "the" square root is generally taken to mean the principal square root.
quote:I have googled square root definition and have noticed that you are dead wrong. Even your own link from wolfram shows you to be wrong.
I'm sure you googled the square root definition by now and you've probably noticed not a single page contradicts what I've stated here.
quote:Sure it does. Imaginary numbers are used all the time in my field, and NOBODY I have ever met uses sqrt(x)=+-y.
Common usage would also say sqrt(-4) doesn't exist. See what happens when you lose precision by bringing semantics into the argument?
quote:You must be a fan of that crappy ass movie Avatar.
The fight is on. There is no quit in atmag's failures. They're quite entertaining.
quote:quote:You must be a fan of that crappy ass movie Avatar.
The fight is on. There is no quit in atmag's failures. They're quite entertaining.
quote:So sqrt(a) is positive, and -sqrt(a) is negative. Furthermore, when denoting both roots, one uses +/-sqrt(a).
Every positive number a has two square roots: sqrt(a), which is positive, and -sqrt(a), which is negative. Together, these two roots are denoted +/-sqrt(a) (see shorthand). Although the principal square root of a positive number is only one of its two square roots, the designation "the square root" is often used to refer to the principal square root. For positive a, the principal square root can also be written in exponent notation, as a^1/2.
quote:The function sqrt(..) returns the principle square root in practically every programming and scripting language on Earth including Mathematica and Maple. That is what it is DEFINED as. It's not shorthand for the English phrase: "both square roots of".
The radical definitionally refers to the principle root.quote:
Every non-negative real number a has a unique non-negative square root, called the principal square root, which is denoted by radical(a), where radical is called the radical sign or radix.
You can't just change radical(a) to sqrt(a).
quote:
sqrt (x) = -2 has no real solutions.
quote:
While sqrt(x^2) = abs(x) is true...
sqrt(x^2) = x is also truequote:
sqrt (x) = -2 has no real solutions.
This is incorrect. Square both sides to solve for x. Hint: it's 4.
quote:No it is not. You are dead wrong. The function sqrt(x) is defined to be:
That's how programming was made to play nice with math.

quote:I've written "programming solvers" for the quadratic equation many times. It would be a HUGE pain in the ass if sqrt(x) returned 2 values. As would the mathematical radix operator represented 2 values. They would, in fact, both be worthless. That is why both in mathematics and in programming they only represent the single principle square root.
It makes it a pain in the ass to get correct answers since you have to always run sqrt() twice.
Think about programming a solver for the quadratic equation...
quote:Most numbers have 2 roots, BUT
Wait, MULTIPLE people are trying to argue that only the positive square root is a possible answer? I'm a libarts tard and even I know the solution is always positive and negative because they both give the same square
only represents one of them: the principle root. "sqrt(x)" is the same thing as
. So the expression "sqrt(-4)*sqrt(-9)" is the same thing as "THE principle root of -4 multiplied by THE principle root of -9", which results in ONE number. Not two. quote:You laugh, but you owned yourself on your own link. The radix operator
I don't think he understands the difference between an operation and a function.
It's 8th grade algebra so I understand how he could be having problems.
( and sqrt(x) ) only represents the principle root. Not both. So maybe you should go back to 8th grade algebra again, since you clearly have no idea what you are talking about. quote:It says no such thing. Nowhere does "sqrt" appear on the entire page. The first sentence says:
His own quote from wiki says, as the first sentence, that sqrt(x) always has two values. One positive and one negative.
I also don't think he's ever plotted y=sqrt(x) by hand... Do they even teach children to plot by hand anymore?
quote:There is a difference between "sqrt(x)" and "the square roots of 16". The statement "sqrt(x)" is the same thing as
In mathematics, a square root of a number a is a number y such that y^2 = a, in other words, a number y whose square (the result of multiplying the number by itself, or y y) is a.[url=https://en.wikipedia.org/wiki/Square_root#cite_note-1][1][/url] For example, 4 and 4 are square roots of 16 because 4^2 = (4)^2 = 16.
which is ONLY the principle root. It is not both roots. Which is why it later says:quote:(I had to plug in images because texAgs can't handle special characters)
Every positive number x has two square roots:, which is positive, and -
, which is negative
quote:quote:You laugh, but you owned yourself on your own link. The radix operator
I don't think he understands the difference between an operation and a function.
It's 8th grade algebra so I understand how he could be having problems.( and sqrt(x) ) only represents the principle root. Not both. So maybe you should go back to 8th grade algebra again, since you clearly have no idea what you are talking about.
quote:No there is not. You cannot be more wrong on this. The operation sqrt(x) IS A FUNCTION. It is the same exact thing asquote:quote:You laugh, but you owned yourself on your own link. The radix operator
I don't think he understands the difference between an operation and a function.
It's 8th grade algebra so I understand how he could be having problems.( and sqrt(x) ) only represents the principle root. Not both. So maybe you should go back to 8th grade algebra again, since you clearly have no idea what you are talking about.
No, there is a difference between the sqrt(x) as an operation and the sqrt(x) as a function which is what the article is talking about. Again, you haven't grasped that idea in this entire thread.
which is also a function. Both ALWAYS return ONLY the principle root of x. That is the reason Mathematica and Maple only return a single value for sqrt(x). They aren't software limited to single answers. Both an return multiple answers when it is proper to do so. The reason they never return multiple answers for sqrt(x) is because it is never proper to do so.